SUM OF TWO NUMBER REPRESENTED AS ARRAY

Given two numbers represented by two arrays, write a function that returns sum array. The sum array is an array representation of addition of two input arrays. It is not allowed to modify the arrays.

Input:

The first line of input contains an integer T denoting the number of test cases.
The first line of each test case contains two integers M and N separated by a space. M is the size of arr1 and N is the size of arr2.
The second line of each test case contains M integers which is the input for arr1.
The third line of each test case contains N integers which is the input for arr2.

Output:

Print the sum list.

Constraints:

1 ≤ T ≤ 100
1 ≤ N ≤ M ≤ 1000
0 ≤ arr1[i],arr2[i]≤ 9

Example:

Input:
2
3 3
5 6 3
8 4 2
16 4
2 2 7 5 3 3 7 3 3 6 8 3 0 5 0 6 
4 3 3 8 

Output:
1 4 0 5
2 2 7 5 3 3 7 3 3 6 8 3 4 8 4 4

CODE:

#include <stdio.h>

int main() {

int t,i,j,count=0,n,m;

scanf("%d",&t);

while(t--)

{

    scanf("%d %d",&m,&n);

    int a[m],b[n];

    for(i=0;i<m;i++)

       scanf("%d",&a[i]);

    for(i=0;i<m;i++)

       scanf("%d",&b[i]);

    j=n-1;

    for(i=m-1;i>=m-n;i--)

    {

        int k=a[i]+b[j]+count;

       // printf("k=%d\n",k);

        if(k>=10)

        {

            a[i]=k%10;

            count=k/10;

        }

       else

       {

           a[i]=k;

           count=0;

       }

    

        j--;

    }

 if(count!=0)

  printf("%d ",count);

 for(i=0;i<m;i++)

       printf("%d ",a[i]);

printf("\n");    

}

return 0;

}